2x^2-20x+65=0

Solution for 2x^2-20x+65=0 equation:

Simplifying
2x2 + -20x + 65 = 0

Reorder the terms:
65 + -20x + 2x2 = 0

Solving
65 + -20x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
32.5 + -10x + x2 = 0

Move the constant term to the right:

Add '-32.5' to each side of the equation.
32.5 + -10x + -32.5 + x2 = 0 + -32.5

Reorder the terms:
32.5 + -32.5 + -10x + x2 = 0 + -32.5

Combine like terms: 32.5 + -32.5 = 0.0
0.0 + -10x + x2 = 0 + -32.5
-10x + x2 = 0 + -32.5

Combine like terms: 0 + -32.5 = -32.5
-10x + x2 = -32.5

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -32.5 + 25

Reorder the terms:
25 + -10x + x2 = -32.5 + 25

Combine like terms: -32.5 + 25 = -7.5
25 + -10x + x2 = -7.5

Factor a perfect square on the left side:
(x + -5)(x + -5) = -7.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.